85 lines
2.3 KiB
JavaScript
85 lines
2.3 KiB
JavaScript
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var md = require('markdown-it')(),
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mk = require('./index');
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md.use(mk);
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var input = document.getElementById('input'),
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output = document.getElementById('output'),
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button = document.getElementById('button');
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button.addEventListener('click', function(ev){
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var result = md.render(input.value);
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output.innerHTML = result;
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});
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/*
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# Some Math
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$\sqrt{3x-1}+(1+x)^2$
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# Maxwells Equations
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$\nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t}
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= \frac{4\pi}{c}\vec{\mathbf{j}} \nabla \cdot \vec{\mathbf{E}} = 4 \pi \rho$
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$\nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} = \vec{\mathbf{0}}$ (curl of $\vec{\mathbf{E}}$ is proportional to the time derivative of $\vec{\mathbf{B}}$)
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$\nabla \cdot \vec{\mathbf{B}} = 0$
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\sqrt{3x-1}+(1+x)^2
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c = \pm\sqrt{a^2 + b^2}
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Maxwell's Equations
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\nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t}
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= \frac{4\pi}{c}\vec{\mathbf{j}} \nabla \cdot \vec{\mathbf{E}} = 4 \pi \rho
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\nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} = \vec{\mathbf{0}}
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\nabla \cdot \vec{\mathbf{B}} = 0
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Same thing in a LaTeX array
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\begin{array}{c}
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\nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} &
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= \frac{4\pi}{c}\vec{\mathbf{j}} \nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \\
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\nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \\
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\nabla \cdot \vec{\mathbf{B}} & = 0
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\end{array}
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\begin{array}{c}
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y_1 \\
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y_2 \mathtt{t}_i \\
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z_{3,4}
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\end{array}
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\begin{array}{c}
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x' &=& &x \sin\phi &+& z \cos\phi \\
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z' &=& - &x \cos\phi &+& z \sin\phi \\
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\end{array}
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# Maxwell's Equations
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equation | description
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----------|------------
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$\nabla \cdot \vec{\mathbf{B}} = 0$ | divergence of $\vec{\mathbf{B}}$ is zero
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$\nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} = \vec{\mathbf{0}}$ | curl of $\vec{\mathbf{E}}$ is proportional to the rate of change of $\vec{\mathbf{B}}$
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$\nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} = \frac{4\pi}{c}\vec{\mathbf{j}} \nabla \cdot \vec{\mathbf{E}} = 4 \pi \rho$ | wha?
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*/
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